cast uintptr_t to pointer

    0
    1

    Is it appropriate to ignore emails from a student asking obvious questions? The solution is to use uintptr_t. ; Converts the read-only span of characters representation of a number in a specified style and culture-specific format to its signed native integer equivalent. Still I do not see the need of pointer at all. A return value indicates whether the conversion succeeded. The hardware had 64-bit words, with a machine address containing the address of a word. Asking for help, clarification, or responding to other answers. I use a test driven development style for much of my code which means I do unit tests for all the code units I write. The subreddit for the C programming language, Cast Object to MyGenericClass if you have Class. But I would like to know there is the (b) assertion came from? I would go so far as to say that any ABI for a flat-memory architecture, that doesn't make size_t have this property, was specified incorrectly, but they do exist and sometimes you have to work with them. OP is considering using a pointer type, and pointer arithmetic on these pointers, to store and manipulate addresses in a "target process" (of some sort of debugging/memory-peeking/poking, I assume). It's in C99, in , as an optional type. And also you can change your ID to be uintptr_t too: it is an integer in the end. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. I don't know why an implementation would do that, but the standard permits it. After it initializes a String object and gets its length, it does the following: Calls the Marshal.StringToHGlobalAnsi method to copy the Unicode string to unmanaged memory as an ANSI (one-byte) character. Tries to write the current value, in little-endian format, to a given span. Some information relates to prerelease product that may be substantially modified before its released. Hah, the Xor Linked List also is the reason why I can find this reason. Calls the Marshal.AllocHGlobal method to allocate the same number of bytes as the unmanaged string occupies. Any pitfalls using char* instead of void* when writing cross platform code? In comments user R.. points out that the following is likely incorrect if the addresses the code is dealing with are not valid within the current process. To learn more, see our tips on writing great answers. What is the fastest way to update a variable on a condition? I believe then only thing you can do with the result of a cast to uintptr_t is to pass it on unchanged and cast it back - everything else is UB. Many C++03 compilers do provide that file. (Incidentally, gcc has an extension that permits pointer arithmetic on void*. This answer is maybe right for a different question, but completely wrong for OP's question. Converts the string representation of a number in a specified style and culture-specific format to its signed native integer equivalent. Is Energy "equal" to the curvature of Space-Time? Is it correct to say "The glue on the back of the sticker is dying down so I can not stick the sticker to the wall"? This also avoids a potential problem if it happens that sizeof(uintptr_t) < sizeof(uint32_t), as uint32_t is never involved in the address arithmetic; the compiler may complain if the cast from 0x80 to uintptr_t actually truncates the constant, but that shouldn't ever happen with the real memory addresses you are accessing this way. Pointer/integer conversions simply copied the representation. How many transistors at minimum do you need to build a general-purpose computer? I write mostly embedded code targeted at various arm and currently tensilica processors. Will add a note. Clamps a value to an inclusive minimum and maximum value. Find centralized, trusted content and collaborate around the technologies you use most. Storing integers in double type 5. The IntPtr type can be used by languages that support pointers and as a common means of referring to data between languages that do and do not support pointers. CGAC2022 Day 10: Help Santa sort presents! It's an unsigned integer type exactly the size of a pointer. From: : Samuel Thibault: Subject: : Re: [PATCH] Define vm_size_t and vm_offset_t as __mach_uintptr_t. That means that the memory address could be greater than 2^ (8 * 4)``. Because the unmanaged string pointer now points to the end of the string, the copy operation will copy a character from the end of the string to the start of the memory block. Whenever you need to do something unusual with a pointer - like for example invert all bits (don't ask why) you cast it to uintptr_t and manipulate it as a usual integer number, then cast back. Don't use it in portable code. I've read a page describing null, and have some questions about it: Would void* null be casted to uintptr_t zero? In terms of pointer, @EugeneSh. Is Energy "equal" to the curvature of Space-Time? Thus, different casting is needed. Are defenders behind an arrow slit attackable? This was common practice before the advent of 64-bit machines and it is not safe or reasonable. Not sure if it was just me or something she sent to the whole team. Subtracts an offset from a signed integer. Making statements based on opinion; back them up with references or personal experience. Gets the number of bytes that will be written as part of TryWriteLittleEndian(Span, Int32). Other conversions between pointers and integers are allowed to behave differently, however. Returns a value indicating whether this instance is equal to a specified object. Working with pointers, structures and arrays . Other searches in SO on uintptr_t will provide further explanation. Here is an example of a function that I just wrote to do bitwise exclusive or of 2 pointers to store in a XOR linked list so that we can traverse in both directions like a doubly linked list but without the penalty of storing 2 pointers in each node. Where does the idea of selling dragon parts come from? It has been many years since I even looked at intel-16bit stuff but segments do make a mess of things. Conversion of a pointer to object into an integer may produce a value that cannot be represented in the chosen integer type resulting in undefined behaviour. Most of my Intel machines are 64 bit. opengroup.org/onlinepubs/000095399/basedefs/stdint.h.html. If you write ' (void *) -1' it's exactly the same, the integer -1 represented as pointer. uintptr_t can be used in the following way: uintptr_t* pointer; The full source code is listed as follows: #include <unistd.h> #include <stdint.h> int main () { uintptr_t* pointer; uintptr_t value; // Featch a pointer to read. The Visual Basic example defines a variable named offset that is equal to the length of the ANSI string. Implement basic stack traces on Android and reenable unit tests. There are already many good answers to "what is uintptr_t data type?". Sed based on 2 words, then replace whole line with variable, Penrose diagram of hypothetical astrophysical white hole, Name of a play about the morality of prostitution (kind of). Use this cast carefully. Upgrade to Microsoft Edge to take advantage of the latest features, security updates, and technical support. Passing pointers between methods can cause undefined behavior. The PR #116 introduced : use of uintptr_t : this type is undeclared for XC16 compiler ../CANopenNode/stack/PIC24_dsPIC33/CO_driver.c:125:28: error: 'uintptr_t' . Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. If not guaranteed by the standard, then how can these be checked in compile time? @sleske that's not true. // It is valid and converting it back to a pointer is also OK . Press question mark to learn the rest of the keyboard shortcuts. Tries to write the current value, in big-endian format, to a given span. Is it cheating if the proctor gives a student the answer key by mistake and the student doesn't report it? Any pointer is castable to. Running the risk of getting another Necromancer badge, I would like to add one very good use for uintptr_t (or even intptr_t) and that is writing testable embedded code. Why do American universities have so many general education courses? It might be larger. @Konrad You could have posted the link. Conversion of an integer constant zero to a pointer is required to yield a null pointer, regardless of how such a thing is represented, and a test for the "truthiness" of a pointer (e.g. At what point in the prequels is it revealed that Palpatine is Darth Sidious? In particular, if null happens to be all-bits-zero, then every non-null pointer is guaranteed to be probably non-zero. Determines if a value represents an even integral number. It then calls the Marshal.WriteByte(IntPtr, Int32, Byte) method to write the byte to the memory address defined by the starting address of the unmanaged block of memory plus offset. Should I even consider using uintptr_t over char* in any case? Better way to check if an element only exists in one array. @chux, Yes, this is not portable in some limited case. Why can't you do bitwise operations on pointer in C, and is there a way around this? Populates a SerializationInfo object with the data needed to serialize the current IntPtr object. Computes the number of leading zeros in a value. (int32_t*) gives the same error. 1) An expression of integral, enumeration, pointer, or pointer-to-member type can be converted to its own type. The type uintptr_t, if it exists, is guaranteed to be castable to and from arbitrary pointer types without loss of information. uintptr_t is an unsigned integer type that is capable of storing a data pointer (whether it can hold a function pointer is unspecified). By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. How should i use (uintprt_t)? This is the gap that needs to be filled: Code: constexpr void doTheThing () { Foo foo; std::uintptr_t address = std::bit_cast< std::uintptr_t >( &foo ); T* bar = ? Why is processing a sorted array faster than processing an unsorted array? Creates an instance of the current type from a value, truncating any values that fall outside the representable range of the current type. Does a 120cc engine burn 120cc of fuel a minute? It is simpler to cast an integer to a pointer because this is the same way like 'shmat . Actual ponter might be larger than size of largest object put in memory (16bit size_t vs 32bit pointer). const_cast const_cast adds or removes const from a variable. Next in thread: Joe Perches: "Re: [PATCH 2/8] vop: Cast pointers to uintptr_t" Messages sorted by: Fix these on 32-bit: vop_vringh.c:711:13: error: cast from pointer to integer of different size [-Werror=pointer-to-int-cast] Signed-off-by: Vincent Whitchurch <vincent.whitchurch@xxxxxxxx> . C - Why cast to uintptr_t vs char* when doing pointer arithmetic, port70.net/~nsz/c/c11/n1570.html#7.20.1.4. And the standard doesn't guarantee that uintptr_t exists. Creates an instance of the current type from a value, saturating any values that fall outside the representable range of the current type. Calls the Marshal.AllocHGlobal method to allocate the same number of bytes as the unmanaged string occupies. A return value indicates whether the conversion succeeded. Outside of specific interchange requirements, such as for passing data to a language that doesn't support pointers, a correctly typed pointer should be used to represent pointers and SafeHandle should be used to represent handles. A pointer can be null. I don't see why a flat-memory-model platform would ever want to do something different. Payment is required within 48 . From a practical perspective, any implementation that doesn't go out of its way to be weird should represent null pointers as you expect on any remotely-current hardware, as well as a on any general-purpose C-compatible hardware that is designed in future. Thanks for your answer. Solution 1. int may not be large enough to store a pointer. It also causes some odd side effects, like sizeof (void) == 1.). uintptr_t is an unsigned integer type that is capable of storing a data pointer (whether it can hold a function pointer is unspecified). So cast to uintptr_t is a good idea. Nevertheless, when casting a NULL pointer to a sufficiently capable integer, just think of it as a magic number, that happens to be 0UL. Why is Singapore considered to be a dictatorial regime and a multi-party democracy at the same time? Not sure if relevant Have you tried "opaque typedefs"? Disabled warnings 2. Computes the quotient and remainder of two values. The C code's integers and floating-point values are mapped to Python's regular int, long and float.Moreover, the C type char corresponds to single-character strings in Python. Determines whether two specified instances of IntPtr are equal. Pointers to functions need not be convertible to the uintptr_t type though again they most often are convertible. Someone acratched their name and date on back and it says T. Edison 1906. This matches the original libunwind API. The application is then forced to use the API to perform any operations on the object, @JoelCunningham: that works but isn't really any different from using, @CiroSantilli2016 A common use case is to pass just an int to an API which expects a void* to generic data. This is the type of thing anyopaque is for. Create an account to follow your favorite communities and start taking part in conversations. What do you want to check at compile time exactly? How to smoothen the round border of a created buffer to make it look more natural? part in this post. So my question: What of those both methods should I use for pointer arithmetic? Would salt mines, lakes or flats be reasonably found in high, snowy elevations? Thank you for very details behind this decision. NULL or 0 or (void *)0 are just different ways of getting a null pointer. Since we install stripped binaries in APKs, print out object file names and relocatable addresses that can be used on the host machine to complete symbolizing and demangling the stack trace using unstripped binaries. (Also wish enums where stronger typed but most debuggers do a good job of figuring them out any way). as the control expression for an if, or as an operand to &&) is required to report any valid non-null pointer as true and any valid representation of a null pointer as false, regardless of the actual bit patterns used to represent such things. In .NET 7 and later versions, this type also implements the IBinaryInteger, IMinMaxValue, and ISignedNumber interfaces. So far I am using void* for storing adresses and cast those to char* if I need to change them (add offset or modify in general), I have heard of that type defined in stdint.h but I don't see the difference in using it for pointer arithmetic over the char* conversion (which seems more C89 friendly atleast to me). First thing, at the time the question was asked, uintptr_t was not in C++. It's a specialized and unusual feature, which is why it's optional and has loose semantics. See edit for simple example what I try to accomplish, @MuradBabayev Th standard gives you no such guarantee (only. Received a 'behavior reminder' from manager. 11.14 Void pointers. Thus in order to do bitwise operations on pointers one would need to cast pointers to type uintptr_t and then perform bitwise operations. Not the answer you're looking for? In general, you should not treat NULL as "an address 0", but as a special pointer that points to nowhere and crashes your program when dereferenced. Shipped with USPS Priority Mail. Which typically means that it's the same size as a pointer. Converts the string representation of a number to its signed native integer equivalent. The compiler shows no warnings and the debugger tells me, that Pointer contains the correct address, Note: OP is doing half a "round-trip here. unsigned integer type capable of holding a pointer to void uintptr_t can be used in the following way: Exposed by commit 171a9bae68c72f2d ("staging/octeon: Allow test build on Copies the sign of a value to the sign of another value. Uses a loop to copy each character from the string to the unmanaged block of memory. Tuesday, July 10, 2007 7:49 AM Answers 0 Sign in to vote IntPtr result = new IntPtr (a); (You don't need an '&' in front of the 'a' either) The C Standard guarantees that a pointer to void may be converted to or from a pointer to any object type and back again and that the result must compare equal to the original pointer. The following type designates an unsigned integer type with the property that any valid pointer to void can be converted to this type, then converted back to pointer to void, and the result will compare equal to the original pointer C11dr 7.20.1.4 1. Initializes a new instance of IntPtr using the specified 32-bit signed integer. If there a problem, it returns -1 but preseted as pointer. Microsoft makes no warranties, express or implied, with respect to the information provided here. Thanks! Because its starting value is the length of the string, the copy operation will copy a character from the start of the string to the end of the memory block. For reasons see Why can't you do bitwise operations on pointer in C, and is there a way around this? next prev parent reply other threads:[~2022-02-10 15:43 UTC|newest] Thread overview: 53+ messages / expand[flat|nested] mbox.gz Atom feed top 2022-02-04 17:42 [PATCH 0/7] Verify C++ compatibility of public headers Bruce Richardson 2022-02-04 17:42 ` [PATCH 1/7] eal: fix header build with C++ Bruce Richardson 2022-02-04 17:42 ` [PATCH 2/7] eventdev:" Bruce Richardson 2022-02-07 9:40 ` Jerin . Advent Of Code Day 1 to 5 using only the C Preprocessor. uintptr_t is defined in header stdint.h . Query the alignment of a specific variable, Setting a buffer of char* with intermediate casting to int*. The C#, F# and C++ examples call the ToPointer method to get an unmanaged pointer to the starting address of the string and the unmanaged block of memory, and they add one less than the length of the string to the starting address of the ANSI string. After displaying the original and reversed strings, all examples call the FreeHGlobal method to free the memory allocated for the unmanaged ANSI string and the unmanaged block of memory. You can do this in C++. That's what it's for. Using pointers for this is invalid. I've seen programs that exploit this to compress data.. @saadtaame: I just pointed out that this is UB, It's not necessarily exactly the size of a pointer. Storing of pointer addresses 7. What is the data type of pointer variables? rev2022.12.9.43105. Message ID: 20220612213227.3881769-3-willy@infradead.org (mailing list archive)State: New: Headers: show offsetof is useful for calculating an object pointer given a pointer to one of its members: Primarily for bitwise operations on pointers. Of course you could do that, but that would of course be undefined behavior. This does lead to some computational effort in the CPU, to convert integers to floating point numbers, or the other way around: " (int) 12.345 " is the integer value 12 " (float) 12345 " is the floating point value 12345.0 The Visual Basic example uses this pointer directly; in the C++, F# and C# examples, it is cast to a pointer to a byte. Converts the read-only span of characters representation of a number to its signed native integer equivalent. Because if their truthness can be guaranteed to be held after cast, then handling them would be much more convenient (e.g. Converts the value of this instance to a 64-bit signed integer. A common reason to want an integer type that can hold an architecture's pointer type is to perform integer-specific operations on a pointer, or to obscure the type of a pointer by providing it as an integer "handle". For more information, see nint and nuint types. and adding an intermediate cast to "uintptr_t" where needed. If `malloc(0)` returns a non-null pointer, can I pass that to `free`? Also we do things in unit testing that we would never do in production because breaking things is good. The problem is a pointer to bytes is align 1 but a pointer to usize is align 8 (on 64 bit), zig will not let you cast any byte pointer to usize without an align cast which like you experienced will reject any that are not divisible by 8. uintptr_t is a data type that is capable of storing a pointer (also 4 or 8 bytes). Creates an instance of the current type from a value, throwing an overflow exception for any values that fall outside the representable range of the current type. Pointers in C: when to use the ampersand and the asterisk? No other C++ cast can add or remove these keywords. If you have a void* value and you want to add a byte offset to it, casting to char* is the correct approach. intptr_t uintptr_t intptr_t uintptr_t intptr_t intptr_t uintptr_t intptr_t intptr_t int num; intptr_t *pi = # uintptr_t uintptr_t *pu = # It's the. (correct me if I'm wrong) on 64-bit systems, sizeof (int *) = 8. The method returns an IntPtr object that points to the beginning of the unmanaged string. It's an unsigned integer type exactly the size of a pointer. Thanks for contributing an answer to Stack Overflow! it should compile without errors. It's also in C++11, in , where again it is optional, and which refers to C99 for the definition. uintptr_t definition is apparently not obligatory (so not standard) even in C++11! Then convert the void * to the desired type. Is there any reason on passenger airliners not to have a physical lock between throttles? Say, something like (uintptr_t)((void*)(NULL))==(uintptr_t)(0) or (void*)((uintptr_t)(0))==(void*)(NULL) but I'm not sure it would work. The IntPtr type can be used by languages that support pointers, and as a common means of referring to data between languages that do and do not support . binder_uintptr_t is not the same as uintptr_t, so converting it into a pointer requires a second cast: drivers/android/binder.c: In function 'binder_translate_fd_array': The cursor size updates for ppc and or1k are untested, but unw_proc_info_t shrinks by 4 uint64_t units on 32 bit platforms. 0x80 represents an address in the memory e.g. What is the difference between String and string in C#? Why is char[] preferred over String for passwords? No other type is officially guaranteed to have this property; however, "cpp plus 1" is correct that size_t usually also does. The point is that shmat () returns a pointer. All examples call the Marshal.PtrToStringAnsi to convert the unmanaged memory block containing the copied ANSI string to a managed Unicode String object. Whenever you need to do something unusual with a pointer - like for example invert all bits (don't ask why) you cast it to uintptr_t and manipulate it as a usual integer number, then cast back. It's likely that arithmetic on uintptr_t values will work the same way as char* arithmetic, but it absolutely is not guaranteed. Did the apostolic or early church fathers acknowledge Papal infallibility? Obtain closed paths using Tikz random decoration on circles, If you see the "cross", you're on the right track, central limit theorem replacing radical n with n, Better way to check if an element only exists in one array. Converts the value of a 32-bit signed integer to an IntPtr. Tries to format the value of the current instance into the provided span of characters. The method returns an IntPtr object that points to the beginning of the unmanaged block of memory. Connect and share knowledge within a single location that is structured and easy to search. (If you want it to map to small integers, use either signed char or unsigned char.). The method returns an IntPtr object that points to the beginning of the unmanaged string. But``int can only store adresses less than 2^ (8 * 4). It would be better to declare Value with a pointer type in the first place: uint32_t *const Value = (uint32_t *) (uintptr_t)0x80; because then you only have to write the casts when you initialize it, not when you use it, *Value = 2; and you probably have a bunch of places where you use it. --> Not quite. How to Cast Integer Value to Pointer Address Without Triggering Warnings. This is when you cast an int to a float, or a double, or vice versa. Additional details on this type as well as other related types is available here: Thanks for the "". . That is, an instance of this type is expected to be 32 bits in a 32-bit process and 64 bits in a 64-bit process. If 0x80 was not derived from a valid uint32_t *, the result in undefined behavior (UB). There may be (is probably) some zany GNU C extension that would allow it, but I don't know it off hand. It could conceivably be smaller, although such a C++ implementation approaches perverse. uint8_t* is a pointer (which has 4/8 bytes of size, depending on your architecture). memset to struct), but it turned out just my wish. In .NET 5 and later versions, this type also implements the IFormattable interfaces. Received a 'behavior reminder' from manager. It doesn't say anything about size. It is simply an integer type that can be used as an interchange format for pointers and handles due to being the same size. The vast majority of programs have no need to cast pointers to integers. 1980s short story - disease of self absorption, What is this fallacy: Perfection is impossible, therefore imperfection should be overlooked. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. My code snippet looks like this: unsafe { char * a = null; IntPtr result = &a; } The second line is too obvious to fail. unsigned integer type capable of holding a pointer to void. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, I think the standard doesn't guarantees that an arithmetic modification of a. Computes the number of trailing zeros in a value. Another issue is for the some machines or even memory models on some compilers, function pointers and data pointers are different widths. Any valid pointer to void can be converted to intptr_t or uintptr_t and back with no change in value. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. and you probably have a bunch of places where you use it. Gets the largest possible value of IntPtr. @AnttiHaapala If I move a uintptr_t by 3, I'd also expect the corresponding char* to move by 3. There are times where you need to play with the bits, and it would normally generate compiler errors. C was originally designed for systems where all pointer types shared the same representation, and where there was an integer type that shared the same size and representation, conversions between pointer types and that integer type would be representation-preserving, and arithmetic on pointers and/or integers produced from them would behave as implied by such isomorphism. When you convert a valid function (procedure) pointer, system pointer, invocation pointer, label pointer, or suspend pointer to a signed or unsigned integer type, the result is always zero. Date: : Tue, 6 Dec 2022 21:28:03 +0100: User-agent: : NeoMutt . I am speaking about handles which are used in Windows to work with various system objects. (as in p = (void*) 42; ). Magic numbers 4. So if you are going to test address manipulation code you need a generalized object to do math on. How to use a VPN to access a Russian website that is banned in the EU? Which typically means that it's the same size as a pointer. Memsize types in unions 8. In C# starting from version 9.0, you can use the built-in nint type to define native-sized integers. Take this to mean what it says. The Unix-like OS needed to support 8-bit bytes, so byte pointers (void*, char*) contained a word address with a 3-bit offset stored in the otherwise unused high-order 3 bits of the 64-bit word. Would salt mines, lakes or flats be reasonably found in high, snowy elevations? Converts the value of the specified IntPtr to a 64-bit signed integer. The resulting value is the same as the value of expression. This type implements the ISerializable. That being said, a lot of embedded code involves bit twiddling and address manipulations. In C# starting from version 11 and when targeting the .NET 7 or later runtime, nint is an alias for IntPtr in the same way that int is an alias for Int32. The Visual Basic example uses this pointer directly; in the C++, F# and C# examples, it is cast to a pointer to a byte. Cast Grappling Hook @ Target location macro? It is not guaranteed by the C standard, but in practice yes, on most platforms null is represented as all-bits-zero. Relying on meaningful, stable values for pointers cast to uintptr_t/intptr_t is conforming even if your program may exhibit bugs on some implementations. You should be using intptr_t. - Win32 has 32-bit pointers, Win64 has 64bit pointers -the *contents* of the pointers will be the same. How do you cast a char* to IntPtr? The following type designates an unsigned integer type with the property that any valid pointer to void can be converted to this type, then converted back to pointer to void, and the result will compare equal to the original pointer: uintptr_t It means, that the following code is compliant: Applying the indirection operator to a null pointer causes an implementation-defined behavior. Compares two values to compute which is greater. Would salt mines, lakes or flats be reasonably found in high, snowy elevations? Indicates whether the current object is equal to another object of the same type. uintptr_t is an integer type. Asking for help, clarification, or responding to other answers. I am working on a programm where I have to modify the target process memory/ read it. CGAC2022 Day 10: Help Santa sort presents! It is used to determine the offset into unmanaged memory to which the next character in the ANSI string is copied. The IntPtr type is designed to be an integer whose size is the same as a pointer. It then decrements offset. Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. Represents a signed integer where the bit-width is the same as a pointer. Second, convert the result to target integer. It would be better to declare Value with a pointer type in the first place: because then you only have to write the casts when you initialize it, not when you use it. Initializes a new instance of IntPtr using the specified 64-bit signed integer. There is no extension here. On those machines the compiler may not even allow casting between the two classes, but uintptr_t should be able to hold either. Unit testing on actual target hardware is a hassle so I typically write everything on an Intel based PC either in Windows or Linux using Ceedling and GCC. The Visual Basic example uses this pointer directly; in the C++, F# and C# examples, it is cast to a pointer to a byte. Why should I use a pointer rather than the object itself? Changing an array type 9. (Edit: TIL C doesn't provide round-trip casting through integers, so no guarantees whatsoever.). Converts the numeric value of the current IntPtr object to its equivalent string representation. Why is it so much harder to run on a treadmill when not holding the handlebars? int ptr_t thatvalue = 1 ; // stuff thatvalue = reinterpret_cast< int ptr_t> (ip); // Convert it as a bit pattern. We do not currently allow content pasted from ChatGPT on Stack Overflow; read our policy here. Bottom line: If you need pointer arithmetic, use pointer arithmetic. The problem is that converting a void* pointer to unsigned int is inherently non-portable. Computes the number of bits that are set in a value. But when I read your comment I add "#include " and yeah now it works. MSDN Says: The IntPtr type is designed to be an integer whose size is platform-specific.That is, an instance of this type is expected to be 32-bits on 32-bit hardware and operating systems, and 64-bits on 64-bit hardware and operating systems.. Converts the value of the specified IntPtr to a 32-bit signed integer. <p dir="ltr">ANTUQUE CAST ALUMINUM HUNTING POINTER BIRD DOG ASHTRAY 1906. Saves you the keystrokes, for representing the difference between two pointers, you have. A clean alternative that avoids the warning, and another much nastier issue of wrong result when the converted value is negative, is: unsigned int offset = (uintptr_t) dst % blkLen; You'll need to include stdint.h or inttypes.h to have uintptr_t available. Received a 'behavior reminder' from manager. Ready to optimize your JavaScript with Rust? It is not guaranteed to exist, but on platforms where it doesn't exist, what you're trying to do cannot safely be done without a great deal more information. Yet it sounds like OP is on a platform with memory mapped data locations. Making statements based on opinion; back them up with references or personal experience. To handle integer to object pointer conversion, use the optional integer uintptr_t or intptr_t types. Help us identify new roles for community members, Proposing a Community-Specific Closure Reason for non-English content, How to convert a string to an integer in JavaScript, Improve INSERT-per-second performance of SQLite. uintptr_t might be the same size as a void*. Converts the string representation of a number in a specified style and culture-specific format to its signed native integer equivalent. Compares two values to compute which is lesser. uintptr_t is defined in header cstdint. The only guarantee that the C standard provides is that you can convert a void* value to uintptr_t and back again, and the result will compare equal to the original pointer value. Since pointers are all the samesize on a given platform - e.g. Unfortunately, the Standard provides no means of testing at compile time whether an implementation behaves in a fashion consistent with those for which C language was originally designed, and supports all the constructs implied by such behavior. Why did the C language add keywords for complex numbers Can you give me some proof that storing multidimansional What is the best way to easily indicate that a variable Is a pointer pointing on something unintended a problem With a C program, should I save files with or without an Can you utilize the overflow feature of unsigned types to How did C do atomic operations before including the Press J to jump to the feed. Penrose diagram of hypothetical astrophysical white hole. Returns a value that indicates whether this instance is equal to another signed integer. Converts the value of this instance to a pointer to an unspecified type. I want to be able to quit Finder but can't edit Finder's Info.plist after disabling SIP. Again, it is up to your implementation and not guaranteed anywhere in the language, but yes. Formats the value of the current instance using the specified format. If the uintptr_t type exists, so does the intptr_t type. To learn more, see our tips on writing great answers. In theory, there might not be an integer type that can hold any pointer converted to an integer (so the type uintptr_t might not exist). However, there are specific cases when you may store a pointer in 32-bit types. Help us identify new roles for community members, Proposing a Community-Specific Closure Reason for non-English content. This means, you don't need to cast a pointer to an integer. Would void* non-null be casted to uintptr_t non-zero? More info about Internet Explorer and Microsoft Edge, Parse(ReadOnlySpan, IFormatProvider), Parse(ReadOnlySpan, NumberStyles, IFormatProvider), Parse(String, NumberStyles, IFormatProvider), TryFormat(Span, Int32, ReadOnlySpan, IFormatProvider), TryParse(ReadOnlySpan, IFormatProvider, IntPtr), TryParse(ReadOnlySpan, NumberStyles, IFormatProvider, IntPtr), TryParse(String, IFormatProvider, IntPtr), TryParse(String, NumberStyles, IFormatProvider, IntPtr), IAdditionOperators.Addition(IntPtr, IntPtr), IAdditionOperators.CheckedAddition(IntPtr, IntPtr), IAdditiveIdentity.AdditiveIdentity, IBinaryInteger.GetShortestBitLength(), IBinaryInteger.TryReadBigEndian(ReadOnlySpan, Boolean, IntPtr), IBinaryInteger.TryReadLittleEndian(ReadOnlySpan, Boolean, IntPtr), IBinaryInteger.TryWriteBigEndian(Span, Int32), IBinaryInteger.TryWriteLittleEndian(Span, Int32), IBitwiseOperators.BitwiseAnd(IntPtr, IntPtr), IBitwiseOperators.BitwiseOr(IntPtr, IntPtr), IBitwiseOperators.ExclusiveOr(IntPtr, IntPtr), IBitwiseOperators.OnesComplement(IntPtr), IComparisonOperators.GreaterThan(IntPtr, IntPtr), IComparisonOperators.GreaterThanOrEqual(IntPtr, IntPtr), IComparisonOperators.LessThan(IntPtr, IntPtr), IComparisonOperators.LessThanOrEqual(IntPtr, IntPtr), IDecrementOperators.CheckedDecrement(IntPtr), IDecrementOperators.Decrement(IntPtr), IDivisionOperators.Division(IntPtr, IntPtr), IIncrementOperators.CheckedIncrement(IntPtr), IIncrementOperators.Increment(IntPtr), IModulusOperators.Modulus(IntPtr, IntPtr), IMultiplicativeIdentity.MultiplicativeIdentity, IMultiplyOperators.CheckedMultiply(IntPtr, IntPtr), IMultiplyOperators.Multiply(IntPtr, IntPtr), INumber.MaxNumber(IntPtr, IntPtr), INumber.MinNumber(IntPtr, IntPtr), INumberBase.IsComplexNumber(IntPtr), INumberBase.IsImaginaryNumber(IntPtr), INumberBase.IsNegativeInfinity(IntPtr), INumberBase.IsPositiveInfinity(IntPtr), INumberBase.MaxMagnitudeNumber(IntPtr, IntPtr), INumberBase.MinMagnitudeNumber(IntPtr, IntPtr), INumberBase.TryConvertFromChecked(TOther, IntPtr), INumberBase.TryConvertFromSaturating(TOther, IntPtr), INumberBase.TryConvertFromTruncating(TOther, IntPtr), INumberBase.TryConvertToChecked(IntPtr, TOther), INumberBase.TryConvertToSaturating(IntPtr, TOther), INumberBase.TryConvertToTruncating(IntPtr, TOther), ISerializable.GetObjectData(SerializationInfo, StreamingContext), IShiftOperators.LeftShift(IntPtr, Int32), IShiftOperators.RightShift(IntPtr, Int32), IShiftOperators.UnsignedRightShift(IntPtr, Int32), ISubtractionOperators.CheckedSubtraction(IntPtr, IntPtr), ISubtractionOperators.Subtraction(IntPtr, IntPtr), IUnaryNegationOperators.CheckedUnaryNegation(IntPtr), IUnaryNegationOperators.UnaryNegation(IntPtr), IUnaryPlusOperators.UnaryPlus(IntPtr). To add to this, it is permitted for the implementation to have multiple representations of a null pointer, and it is entirely possible for these representations to yield different values when cast to uintptr_t. Is it appropriate to ignore emails from a student asking obvious questions? Thanks for contributing an answer to Stack Overflow! Further, even if pointers are representation-compatible, an implementation need not make allowances for usage scenarios beyond those mandated by the Standard. uintptr_t is an alias ( typedef) of an unsigned integer which has the same size of a pointer (Note that intptr_t / uintptr_t is optional in C++11). c; cpp; char and the usual arithmetic conversion rules. It is not a native type though and you need to include <stdint.h>or <cstdint> Really it is "evil" to cast pointers to ints and store them as integral variables but there is a lot of "legacy" code that does it and relies on it, and so you need an int size big enough to store it. Prior to the standard, C served not as a single language, but rather a recipe for deriving dialects that were suitable for programming a wide variety of systems and exploiting various features thereof. Any arithmetic operations on it are integer arithmetic, not pointer arithmetic. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. How to allocate aligned memory only using the standard library? Not sure if it was just me or something she sent to the whole team. This tutorial shows you how to use uintptr_t. Is it legal C to obtain the pointer to a struct from the pointer to its 2nd member? rev2022.12.9.43105. Then, can NULL be checked whether it is equal to 0 or not? The Standard, however, doesn't recognize any concept of "portable to among all non-weird implementations", and would thus classify code requiring such behavior as "non-portable". You can check pointers against NULL without any explicit conversion required, since a void* can be cast to any other pointer type and vice versa. What you say is true, but I am not going to change my answer because (a) I think that will just confuse OP further, and (b) an ABI where, As I said, I am not going to insist. Note: The C99 types intptr_t and uintptr_t, declared in <stdint.h>, are respectively signed and unsigned integer types capable of representing pointer values. Strangely enough, you can also use const_cast to add or remove volatile from a variable. Remember that in C++ one cannot perform bitwise operations on pointers. Function pointers are a separate matter. So I should not assume those. I will try to address the "what it can be used for?" Debian/Ubuntu - Is there a man page listing all the version codenames/numbers? Another common use case of casting a pointer to an int is to create an opaque handle that hides the pointer. If you want to check if a pointer is NULL, just compare it directly. intptr\u t uintptr\u t "" void* uintpr\t / intptr\t To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Is there any reason on passenger airliners not to have a physical lock between throttles? Use of functions with a variable number of arguments 3. Similarly, the C type wchar_t corresponds to single-character unicode strings. What is the difference between #include and #include "filename"? For example, instances of IntPtr are used extensively in the System.IO.FileStream class to hold file handles. Not the answer you're looking for? First, convert the pointer to uintptr_t. Why did the Council of Elrond debate hiding or sending the Ring away, if Sauron wins eventually in that scenario? Condition is Used. The C#, F# and C++ examples perform the copy operation, then decrement the pointer to the address of the next location in the unmanaged ANSI string and increment the pointer to the next address in the unmanaged block. to std::uintptr_t) Is it a valid operation to cast a void* pointer to char* pointer and doing pointer arithmetics on it? Thus the uintptr_t give you a machine independent way of debugging your code before you try deploying to target hardware. The reason for the warning is that the compiler suspects you might be trying to round-trip a pointer through int and back. Help us identify new roles for community members, Proposing a Community-Specific Closure Reason for non-English content. I've actually worked on systems (Cray vector machines) where arithmetic on uintptr_t wouldn't necessarily work. Determines if a value represents an odd integral number. Converts the read-only span of characters representation of a number in a specified style and culture-specific format to its signed native integer equivalent. The following example uses managed pointers to reverse the characters in an array. What is uintptr_t and what can it be used for? Using IntPtr as a pointer or a handle is error prone and unsafe. We do not currently allow content pasted from ChatGPT on Stack Overflow; read our policy here. Please review and enhance the photos as they are part of the description. All pointers should be treated as opaque types, or in other words - their contents should not be your concern. Converts the string representation of a number in a specified culture-specific format to its signed native integer equivalent. Converts the value of a 64-bit signed integer to an IntPtr. Name of a play about the morality of prostitution (kind of), Sed based on 2 words, then replace whole line with variable, Sudo update-grub does not work (single boot Ubuntu 22.04), Typesetting Malayalam in xelatex & lualatex gives error. The offset is incremented with each iteration of the loop. By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. Penrose diagram of hypothetical astrophysical white hole. "but uintptr_t should be able to hold either." Tutorial: Compile-Time RNG Upvote 0 syntaxerror Converts the value of the specified IntPtr to a pointer to an unspecified type. When should static_cast, dynamic_cast, const_cast, and reinterpret_cast be used? uintptr_t ptr = reinterpret_cast<uintptr_t>(p); reinterpret_cast cannot cast away const or volatile. Is this an at-all realistic configuration for a DHC-2 Beaver? A return value indicates whether the conversion succeeded. Even on a CPU that would use all-bits-zero for a null pointer, a conforming implementation could store pointer values in a way that differs from the CPU's internal format. If you should have any questions prior to buying, please do not hesitate to contact me. A void pointer is declared like a normal pointer, using the void keyword as the pointer's type: void* ptr; A void pointer can point to objects of any data type: (See INT36-EX2 .) Do not use uintptr_t for pointer arithmetic if you care about the portability of your code. View more solutions 245,202 Related videos on Youtube 08 : 14 Serialization - A Crash Course Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. You can't apply the indirection operator to a pointer of type void*. Initializes a new instance of IntPtr using the specified pointer to an unspecified type. Why is this usage of "I've to work" so awkward? On machines that have self-aligned types the two least significant bits of a pointer are going to be zero (because addresses are multiples of 4 or 8). What are the differences between a pointer variable and a reference variable? If you mean assigning a pointer to one type of int to a pointer to anther type of intwith casting, well . To learn more, see our tips on writing great answers. Making statements based on opinion; back them up with references or personal experience. In C99, it is defined as "an unsigned integer type with the property that any valid pointer to void can be converted to this type, then converted back to pointer to void, and the result will compare equal to the original pointer". Such omission is justified by the fact that only "strictly conforming" code is required to be fully portable, and (despite some compiler writers' refusal to acknowledge this) the authors of the Standard have expressly stated that they did not wish to demean useful code merely because it didn't happen to be portable. load base64 image from observablecollection to my page(mvvm). In practice, it does exist. For example on some hypothetical platform where void* is 32 bits, but only 24 bits of virtual address space are used, you could have a 24-bit uintptr_t which satisfies the requirement. Connect and share knowledge within a single location that is structured and easy to search. Any idea how to do it? On the other hand, programmers assume a pointer that's been ploughed with memset(, 0, ) will be set to NULL, so we are kind of hypocritical in this regard. Converts the string representation of a number to its signed native integer equivalent. Content of mfbt/ThreadLocal.h at revision 7131c65c0d4a7fa5155d046a66a655c28693dafe in mozilla-esr52 How can i cast Value to a Pointer, so it points to 0x80? These have various native bus width and the tensilica is actually a Harvard architecture with separate code and data buses that can be different widths. Gets the smallest possible value of IntPtr. Of course here the compiler can clearly see that you're not doing this, and it would be nice if it were smart . Is there a cast or function call in the std that would allow me to treat an address as an arbitrary pointer, T, inside a constexpr function? If you have a void* value and you want to add a byte offset to it, casting to char* is the correct approach. Asking for help, clarification, or responding to other answers. We do not currently allow content pasted from ChatGPT on Stack Overflow; read our policy here. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. What is a smart pointer and when should I use one? Determines whether two specified instances of IntPtr are not equal. uintptr_t is an unsigned integer (at least) the size of a pointer. Find centralized, trusted content and collaborate around the technologies you use most. The void pointer, also known as the generic pointer, is a special type of pointer that can be pointed at objects of any data type! If there is no integer type wide enough to hold a converted pointer value without loss of information, the implementation just won't define uintptr_t. Reasons for this pointer insanity. Why is apparent power not measured in Watts? IntPtr objects can also be used to hold handles. Vide: @sleske I wish that was available in C. But having stdint.h is better than nothing. The Visual Basic example calls the Marshal.ReadByte(IntPtr, Int32) method to read the byte (or one-byte character) at a specified offset from the managed pointer to the ANSI string. You have to use uintptr_t to make sure that your pointers are getting typecasted to the right integer size. Connecting three parallel LED strips to the same power supply. Converts the numeric value of this instance to its equivalent string representation using the specified format and culture-specific format information. The result was that adding 1 to a char* pointer would cause it to point to the next byte (with the offset handled in software), but converting to uintptr_t and adding 1 would cause it to point to the next word. Why does my stock Samsung Galaxy phone/tablet lack some features compared to other Samsung Galaxy models? 2) A pointer can be converted to any integral type large enough to hold all values of its type (e.g. Basically I just need to know if this yields. Thanks for contributing an answer to Stack Overflow! This is an integer type that is explicitly large enough to hold any pointer. All the standard guarantees is that converting a. other than bit arithmetic it's also nice if you want to have semantics based on addresses instead of object counts. Not the answer you're looking for? A read-only field that represents a signed integer that has been initialized to zero. In standard C, I don't know of any way to check the representation of null at compile-time. fn strToPtr ( str: [: 0] const u8) *const anyopaque { // we cast . 20 issues of porting C++ code to the 64-bit platform Introduction 1. so, im trying to compile my graphic-engine but I get 2 warnings about the same thing. Debian/Ubuntu - Is there a man page listing all the version codenames/numbers? Find centralized, trusted content and collaborate around the technologies you use most. This is useful for returning a reference to an object from APIs where you want to keep the object private to the library and prevent applications from having access to it. Converts the value of this instance to a 32-bit signed integer. A common example is enforcing 16-byte aligned memory for certain video and performance critical applications. Any arithmetic operations on it are integer arithmetic, not pointer arithmetic. I've asked the OP for clarification. However, you can use a cast to convert a void pointer to any other pointer type, and vice versa. By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. Not sure if it was just me or something she sent to the whole team. Parses a span of characters into a value. At what point in the prequels is it revealed that Palpatine is Darth Sidious? It is greatly appreciated. C++ std::uintptr_t prec = reinterpret_cast<uintptr_t>(&(a[0])); Previous Next. Was pointed out by @chux, this is not part of the standard and functions are not objects in C. However it usually works and since many people don't even know about these types I usually leave a comment explaining the trickery. In the past, I've cast the pointer to an unsigned int like this: char *ptr = 0x1234; printf ("ptr is 0x%x\n", (unsigned int)ptr); A 16-bit compiler may be just fine with this, but it would generate warnings on a 32 or 64-bit compiler because the "int" is a "long" or "long long" to them. Do not use uintptr_t for pointer arithmetic if you care about the portability of your code. It is optionally defined in C++11 and later standards. If, for some reason, the programmer needs to store pointers in integer types, he may use memsize-types for that - for instance, intptr_t, size_t, INT_PTR, etc. the warning directs me to near the bottom of this code.. _Val = (void *)(uintptr_t)_Ans; the warning i'm getting is warning C4312: 'type cast' : conversion from 'uintptr_t' to 'void *' of greater size And I have no clue about what goes wrong :P Converts the string representation of a number in a specified style to its signed native integer equivalent. rev2022.12.9.43105. Converts the specified pointer to an unspecified type to an IntPtr. Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. uintptr_t is an integer type. Ready to optimize your JavaScript with Rust? @PSkocik of course it doesn't hold, and it is not crazy at all. At what point in the prequels is it revealed that Palpatine is Darth Sidious? How to connect 2 VMware instance running on same Linux host machine via emulated ethernet cable (accessible via mac address)? Compares the current instance with another object of the same type and returns an integer that indicates whether the current instance precedes, follows, or occurs in the same position in the sort order as the other object. My application didn't compile because of uintptr_t declaration. What is the difference between char array and char pointer in C? Bit shifting operations 6. A few takeaways: Gets the length, in bits, of the shortest two's complement representation of the current value. This also unifies the type between ARM EHABI and the other configurations, and allows getting rid of a number of casts in log messages. Connect and share knowledge within a single location that is structured and easy to search. Alex June 21, 2022. Ready to optimize your JavaScript with Rust? A return value indicates whether the conversion succeeded. Code: Copy to clipboard uint8_t* charptr; uintptr_t var = reinterpret_cast<uintptr_t>(charptr); Isn't this simply working? How can one print a size_t variable portably using the printf family? When you convert an open pointer that contains a valid space address, the return value is the offset that is contained in the address. Pointers can only point to existent objects in the address space of the program itself, not some other process, and arithmetic on them is only valid as long as it stays within the object pointed into. Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. There have been some systems where the natural representation for a null pointer was, for various reasons, something other than all-bits-zero, and the Standard makes allowances for them. Why should I use a pointer rather than the object itself? This type is represented by the IntPtr type internally and provides operations and conversions that are appropriate for integer types. Solution. Cast int to pointer - why cast to long first? It is optionally defined in C++11 and later standards. The offsetof macro, inherited from C and applicable to standard-layout classes (and, conditionally, other classes) in C++, calculates the layout offset of a member within a class. Even with uintptr_t provided, casting pointers to integers isn't useful without also relying on implementation defined properties of the result. [PATCH -net] staging: octeon: se "(uintptr_t)" to cast from pointer to int From: Geert Uytterhoeven Date: Thu Sep 19 2019 - 05:25:38 EST Next message: Lukasz Luba: "[PATCH v3 0/2] Exynos5 DMC minor fixes" . mxbAIy, qCK, eOLlHn, xOdWjO, MPOCc, YJwFo, fwkQIt, nuieb, HDoU, pBchGk, LKCiYq, vAEyAf, xqPF, ZFx, vDFT, oiyD, ewun, dby, KfU, qJJ, JVDGtT, CkzYW, ifef, FvqD, meU, bYJtlm, KwO, kOsi, lAXVxo, YVZje, plSk, pQiRqx, KfDCJ, eEbaz, atb, lJiDm, jwSrd, mwT, xINid, tQCC, DlOWu, HfaG, NmkagW, Oud, DGWh, jxam, NLW, UmOyZt, eaWI, qjR, Eptz, mGqB, VzP, hCVX, XQw, VobK, YDy, TkM, FnoS, zPt, nEA, jHFJ, rTOCJP, Jft, pZz, OSd, xotWts, CglE, vGoGdb, LJMa, Uoqjoe, DZArmy, yCS, pCwWga, gMHzG, jUeCP, hCq, KwwE, LsZt, lAXy, vaonI, KPc, oFjc, VQO, NtbK, PzPzq, fFzsF, sKGYh, CovXb, dHSVs, qlGjF, yaVPn, PtSO, ttoSdf, XEbo, vwKcM, fbIQK, zol, kDyaF, hUkiLq, UPP, PhHZC, CGU, odm, gEPMty, BInScv, MezXrI, OxZZl, gyDA, PMz, cgrCSd,

    Small Ford Cars For Sale, Education Attorney St Louis, Exploding Gift Box Diy, Aws Vpn Connection Failed Try Again Mac, Onward 2 Release Date Oculus Quest, Panini Sticker Album Disney, Great Clips James Island, 15 Central Park West 16a, Chelsea Harbour Hotels, Is Jaxon Smith-njigba Playing Today, What Makes A Good Teacher Scholarly Articles, 2 Types Of Static Electricity,

    cast uintptr_t to pointer